60x2+33x-27=0

Solution for 60x2+33x-27=0 equation:

60x^2+33x-27=0

a = 60; b = 33; c = -27;
Δ = b2-4ac
Δ = 332-4·60·(-27)
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7569}=87$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-87}{2*60}=\frac{-120}{120}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+87}{2*60}=\frac{54}{120}
=9/20
$