60x2+3.3x-27=0

Solution for 60x2+3.3x-27=0 equation:

60x^2+3.3x-27=0

a = 60; b = 3.3; c = -27;
Δ = b2-4ac
Δ = 3.32-4·60·(-27)
Δ = 6490.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.3)-\sqrt{6490.89}}{2*60}=\frac{-3.3-\sqrt{6490.89}}{120}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.3)+\sqrt{6490.89}}{2*60}=\frac{-3.3+\sqrt{6490.89}}{120}
$