3(3x-5)-2=3(x-4)+43

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Solution for 3(3x-5)-2=3(x-4)+43 equation: 



3(3x-5)-2=3(x-4)+43

We move all terms to the left:

3(3x-5)-2-(3(x-4)+43)=0

We multiply parentheses

9x-(3(x-4)+43)-15-2=0



We calculate terms in parentheses: -(3(x-4)+43), so:

3(x-4)+43

We multiply parentheses

3x-12+43

We add all the numbers together, and all the variables

3x+31

Back to the equation:

-(3x+31)



We add all the numbers together, and all the variables

9x-(3x+31)-17=0

We get rid of parentheses

9x-3x-31-17=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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