60(6m-1m)-2=-90m+m(-40m)=4

Solution for 60(6m-1m)-2=-90m+m(-40m)=4 equation:

60(6m-1m)-2=-90m+m(-40m)=4

We move all terms to the left:

60(6m-1m)-2-(-90m+m(-40m))=0

We add all the numbers together, and all the variables

60(+5m)-(-90m+m(-40m))-2=0

We multiply parentheses

300m-(-90m+m(-40m))-2=0


We calculate terms in parentheses: -(-90m+m(-40m)), so:

-90m+m(-40m)

We multiply parentheses

-40m^2-90m

Back to the equation:

-(-40m^2-90m)


We get rid of parentheses

40m^2+90m+300m-2=0

We add all the numbers together, and all the variables

40m^2+390m-2=0

a = 40; b = 390; c = -2;
Δ = b2-4ac
Δ = 3902-4·40·(-2)
Δ = 152420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{152420}=\sqrt{4*38105}=\sqrt{4}*\sqrt{38105}=2\sqrt{38105}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(390)-2\sqrt{38105}}{2*40}=\frac{-390-2\sqrt{38105}}{80}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(390)+2\sqrt{38105}}{2*40}=\frac{-390+2\sqrt{38105}}{80}
$