3(2d-1)=2d=4(d-2)+5

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Solution for 3(2d-1)=2d=4(d-2)+5 equation: 



3(2d-1)=2d=4(d-2)+5

We move all terms to the left:

3(2d-1)-(2d)=0

We add all the numbers together, and all the variables

-2d+3(2d-1)=0

We multiply parentheses

-2d+6d-3=0

We add all the numbers together, and all the variables

4d-3=0

We move all terms containing d to the left, all other terms to the right

4d=3

d=3/4

d=3/4

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