3-(8-x)=4x-2(3x-2)

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Solution for 3-(8-x)=4x-2(3x-2) equation: 



3-(8-x)=4x-2(3x-2)

We move all terms to the left:

3-(8-x)-(4x-2(3x-2))=0

We add all the numbers together, and all the variables

-(-1x+8)-(4x-2(3x-2))+3=0

We get rid of parentheses

1x-(4x-2(3x-2))-8+3=0



We calculate terms in parentheses: -(4x-2(3x-2)), so:

4x-2(3x-2)

We multiply parentheses

4x-6x+4

We add all the numbers together, and all the variables

-2x+4

Back to the equation:

-(-2x+4)



We add all the numbers together, and all the variables

x-(-2x+4)-5=0

We get rid of parentheses

x+2x-4-5=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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