6/7(x+1)=1/28(x+8)

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Solution for 6/7(x+1)=1/28(x+8) equation: 



6/7(x+1)=1/28(x+8)

We move all terms to the left:

6/7(x+1)-(1/28(x+8))=0



Domain of the equation: 7(x+1)!=0

x∈R





Domain of the equation: 28(x+8))!=0

x∈R



We calculate fractions


(168xx/(7(x+1)*28(x+8)))+(-7xx/(7(x+1)*28(x+8)))=0



We calculate terms in parentheses: +(168xx/(7(x+1)*28(x+8))), so:

168xx/(7(x+1)*28(x+8))

We multiply all the terms by the denominator


168xx

Back to the equation:

+(168xx)





We calculate terms in parentheses: +(-7xx/(7(x+1)*28(x+8))), so:

-7xx/(7(x+1)*28(x+8))

We multiply all the terms by the denominator


-7xx

Back to the equation:

+(-7xx)



We get rid of parentheses

168xx-7xx=0

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