6-2(4r+1)=3r-2(2r+5)

Solution for 6-2(4r+1)=3r-2(2r+5) equation:

6-2(4r+1)=3r-2(2r+5)

We move all terms to the left:

6-2(4r+1)-(3r-2(2r+5))=0

We multiply parentheses

-8r-(3r-2(2r+5))-2+6=0


We calculate terms in parentheses: -(3r-2(2r+5)), so:

3r-2(2r+5)

We multiply parentheses

3r-4r-10

We add all the numbers together, and all the variables

-1r-10

Back to the equation:

-(-1r-10)


We add all the numbers together, and all the variables

-8r-(-1r-10)+4=0

We get rid of parentheses

-8r+1r+10+4=0

We add all the numbers together, and all the variables

-7r+14=0

We move all terms containing r to the left, all other terms to the right

-7r=-14

r=-14/-7

r=+2