(x+3)(x+4)=x

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Solution for (x+3)(x+4)=x equation: 



(x+3)(x+4)=x

We move all terms to the left:

(x+3)(x+4)-(x)=0

We add all the numbers together, and all the variables

-1x+(x+3)(x+4)=0

We multiply parentheses ..

(+x^2+4x+3x+12)-1x=0

We get rid of parentheses

x^2+4x+3x-1x+12=0

We add all the numbers together, and all the variables

x^2+6x+12=0

a = 1; b = 6; c = +12;
Δ = b2-4ac
Δ = 62-4·1·12
Δ = -12
Delta is less than zero, so there is no solution for the equation

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