(5+6x)+(-7-2x)=5+(-7)+6x+(-2x)=

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Solution for (5+6x)+(-7-2x)=5+(-7)+6x+(-2x)= equation: 



(5+6x)+(-7-2x)=5+(-7)+6x+(-2x)=

We move all terms to the left:

(5+6x)+(-7-2x)-(5+(-7)+6x+(-2x))=0

We add all the numbers together, and all the variables

(6x+5)+(-2x-7)-(5+(-7)+6x+(-2x))=0

We get rid of parentheses

6x-2x-(5+(-7)+6x+(-2x))+5-7=0



We calculate terms in parentheses: -(5+(-7)+6x+(-2x)), so:

5+(-7)+6x+(-2x)

determiningTheFunctionDomain
6x+(-2x)+5+(-7)

We add all the numbers together, and all the variables

6x+(-2x)-2

We get rid of parentheses

6x-2x-2

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

4x-(4x-2)-2=0

We get rid of parentheses

4x-4x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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