6-2(2x+1)=7x-2(7+x)

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Solution for 6-2(2x+1)=7x-2(7+x) equation: 



6-2(2x+1)=7x-2(7+x)

We move all terms to the left:

6-2(2x+1)-(7x-2(7+x))=0

We add all the numbers together, and all the variables

-2(2x+1)-(7x-2(x+7))+6=0

We multiply parentheses

-4x-(7x-2(x+7))-2+6=0



We calculate terms in parentheses: -(7x-2(x+7)), so:

7x-2(x+7)

We multiply parentheses

7x-2x-14

We add all the numbers together, and all the variables

5x-14

Back to the equation:

-(5x-14)



We add all the numbers together, and all the variables

-4x-(5x-14)+4=0

We get rid of parentheses

-4x-5x+14+4=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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