6-4(2x+1)=10x-4(10+x)

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Solution for 6-4(2x+1)=10x-4(10+x) equation: 



6-4(2x+1)=10x-4(10+x)

We move all terms to the left:

6-4(2x+1)-(10x-4(10+x))=0

We add all the numbers together, and all the variables

-4(2x+1)-(10x-4(x+10))+6=0

We multiply parentheses

-8x-(10x-4(x+10))-4+6=0



We calculate terms in parentheses: -(10x-4(x+10)), so:

10x-4(x+10)

We multiply parentheses

10x-4x-40

We add all the numbers together, and all the variables

6x-40

Back to the equation:

-(6x-40)



We add all the numbers together, and all the variables

-8x-(6x-40)+2=0

We get rid of parentheses

-8x-6x+40+2=0

We add all the numbers together, and all the variables

-14x+42=0

We move all terms containing x to the left, all other terms to the right

-14x=-42

x=-42/-14

x=+3

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