16-2t=(3/2t)+9

Solution for 16-2t=(3/2t)+9 equation:

16-2t=(3/2t)+9

We move all terms to the left:

16-2t-((3/2t)+9)=0


Domain of the equation: 2t)+9)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

-2t-((+3/2t)+9)+16=0

We multiply all the terms by the denominator


-2t*2t)+9)-((+16*2t)+9)+3=0

Wy multiply elements

-4t^2+32t=0

a = -4; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·(-4)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*-4}=\frac{-64}{-8}
=+8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*-4}=\frac{0}{-8}
=0
$