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6+2(x-9)=7-4(x-5)
We move all terms to the left:
6+2(x-9)-(7-4(x-5))=0
We multiply parentheses
2x-(7-4(x-5))-18+6=0
We calculate terms in parentheses: -(7-4(x-5)), so:We add all the numbers together, and all the variables
7-4(x-5)
determiningTheFunctionDomain -4(x-5)+7
We multiply parentheses
-4x+20+7
We add all the numbers together, and all the variables
-4x+27
Back to the equation:
-(-4x+27)
2x-(-4x+27)-12=0
We get rid of parentheses
2x+4x-27-12=0
We add all the numbers together, and all the variables
6x-39=0
We move all terms containing x to the left, all other terms to the right
6x=39
x=39/6
x=6+1/2
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