(4x-5)=2(6x-21)

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Solution for (4x-5)=2(6x-21) equation: 



(4x-5)=2(6x-21)

We move all terms to the left:

(4x-5)-(2(6x-21))=0

We get rid of parentheses

4x-(2(6x-21))-5=0



We calculate terms in parentheses: -(2(6x-21)), so:

2(6x-21)

We multiply parentheses

12x-42

Back to the equation:

-(12x-42)



We get rid of parentheses

4x-12x+42-5=0

We add all the numbers together, and all the variables

-8x+37=0

We move all terms containing x to the left, all other terms to the right

-8x=-37

x=-37/-8

x=4+5/8

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