6(y+4)=1/3(18y+30)

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Solution for 6(y+4)=1/3(18y+30) equation: 



6(y+4)=1/3(18y+30)

We move all terms to the left:

6(y+4)-(1/3(18y+30))=0



Domain of the equation: 3(18y+30))!=0

y∈R



We multiply parentheses

6y-(1/3(18y+30))+24=0

We multiply all the terms by the denominator


6y*3(18y+30))-(1+24*3(18y+30))=0

Wy multiply elements

18y^2(1+72y(1=0

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