5(-8+3b)=10(b+6)

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Solution for 5(-8+3b)=10(b+6) equation: 



5(-8+3b)=10(b+6)

We move all terms to the left:

5(-8+3b)-(10(b+6))=0

We add all the numbers together, and all the variables

5(3b-8)-(10(b+6))=0

We multiply parentheses

15b-(10(b+6))-40=0



We calculate terms in parentheses: -(10(b+6)), so:

10(b+6)

We multiply parentheses

10b+60

Back to the equation:

-(10b+60)



We get rid of parentheses

15b-10b-60-40=0

We add all the numbers together, and all the variables

5b-100=0

We move all terms containing b to the left, all other terms to the right

5b=100

b=100/5

b=20

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