5(-8+3b)=(b+6)

Solution for 5(-8+3b)=(b+6) equation:

5(-8+3b)=(b+6)

We move all terms to the left:

5(-8+3b)-((b+6))=0

We add all the numbers together, and all the variables

5(3b-8)-((b+6))=0

We multiply parentheses

15b-((b+6))-40=0


We calculate terms in parentheses: -((b+6)), so:

(b+6)

We get rid of parentheses

b+6

Back to the equation:

-(b+6)


We get rid of parentheses

15b-b-6-40=0

We add all the numbers together, and all the variables

14b-46=0

We move all terms containing b to the left, all other terms to the right

14b=46

b=46/14

b=3+2/7