6(y+3)-2y=2(2y+1)

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Solution for 6(y+3)-2y=2(2y+1) equation: 



6(y+3)-2y=2(2y+1)

We move all terms to the left:

6(y+3)-2y-(2(2y+1))=0

We add all the numbers together, and all the variables

-2y+6(y+3)-(2(2y+1))=0

We multiply parentheses

-2y+6y-(2(2y+1))+18=0



We calculate terms in parentheses: -(2(2y+1)), so:

2(2y+1)

We multiply parentheses

4y+2

Back to the equation:

-(4y+2)



We add all the numbers together, and all the variables

4y-(4y+2)+18=0

We get rid of parentheses

4y-4y-2+18=0

We add all the numbers together, and all the variables

16!=0

There is no solution for this equation

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