3k-2=2(-k-2)

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Solution for 3k-2=2(-k-2) equation:



3k-2=2(-k-2)
We move all terms to the left:
3k-2-(2(-k-2))=0
We add all the numbers together, and all the variables
3k-(2(-1k-2))-2=0
We calculate terms in parentheses: -(2(-1k-2)), so:
2(-1k-2)
We multiply parentheses
-2k-4
Back to the equation:
-(-2k-4)
We get rid of parentheses
3k+2k+4-2=0
We add all the numbers together, and all the variables
5k+2=0
We move all terms containing k to the left, all other terms to the right
5k=-2
k=-2/5
k=-2/5

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