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X2+2X=9-6X
We move all terms to the left:
X2+2X-(9-6X)=0
We add all the numbers together, and all the variables
X2+2X-(-6X+9)=0
We add all the numbers together, and all the variables
X^2+2X-(-6X+9)=0
We get rid of parentheses
X^2+2X+6X-9=0
We add all the numbers together, and all the variables
X^2+8X-9=0
a = 1; b = 8; c = -9;
Δ = b2-4ac
Δ = 82-4·1·(-9)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-10}{2*1}=\frac{-18}{2} =-9 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+10}{2*1}=\frac{2}{2} =1 $
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