6(y+2)-3y=36

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Solution for 6(y+2)-3y=36 equation: 



6(y+2)-3y=36

We move all terms to the left:

6(y+2)-3y-(36)=0

We add all the numbers together, and all the variables

-3y+6(y+2)-36=0

We multiply parentheses

-3y+6y+12-36=0

We add all the numbers together, and all the variables

3y-24=0

We move all terms containing y to the left, all other terms to the right

3y=24

y=24/3

y=8

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