3i(2+2i)=0

Solution for 3i(2+2i)=0 equation:

3i(2+2i)=0

We add all the numbers together, and all the variables

3i(2i+2)=0

We multiply parentheses

6i^2+6i=0

a = 6; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·6·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*6}=\frac{-12}{12}
=-1
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*6}=\frac{0}{12}
=0
$