(7x-3)+(3x+5)+(x+29)=180

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Solution for (7x-3)+(3x+5)+(x+29)=180 equation: 



(7x-3)+(3x+5)+(x+29)=180

We move all terms to the left:

(7x-3)+(3x+5)+(x+29)-(180)=0

We get rid of parentheses

7x+3x+x-3+5+29-180=0

We add all the numbers together, and all the variables

11x-149=0

We move all terms containing x to the left, all other terms to the right

11x=149

x=149/11

x=13+6/11

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