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5-2/5(d+1)=3
We move all terms to the left:
5-2/5(d+1)-(3)=0
Domain of the equation: 5(d+1)!=0We add all the numbers together, and all the variables
d∈R
-2/5(d+1)+2=0
We multiply all the terms by the denominator
2*5(d+1)-2=0
Wy multiply elements
10d(d-2=0
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