6(2y-5)=2(10+3y)

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Solution for 6(2y-5)=2(10+3y) equation: 



6(2y-5)=2(10+3y)

We move all terms to the left:

6(2y-5)-(2(10+3y))=0

We add all the numbers together, and all the variables

6(2y-5)-(2(3y+10))=0

We multiply parentheses

12y-(2(3y+10))-30=0



We calculate terms in parentheses: -(2(3y+10)), so:

2(3y+10)

We multiply parentheses

6y+20

Back to the equation:

-(6y+20)



We get rid of parentheses

12y-6y-20-30=0

We add all the numbers together, and all the variables

6y-50=0

We move all terms containing y to the left, all other terms to the right

6y=50

y=50/6

y=8+1/3

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