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6(x-4)+3(x+3)-5(2x-5)=8x=3(2x-4)
We move all terms to the left:
6(x-4)+3(x+3)-5(2x-5)-(8x)=0
We add all the numbers together, and all the variables
-8x+6(x-4)+3(x+3)-5(2x-5)=0
We multiply parentheses
-8x+6x+3x-10x-24+9+25=0
We add all the numbers together, and all the variables
-9x+10=0
We move all terms containing x to the left, all other terms to the right
-9x=-10
x=-10/-9
x=1+1/9
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