8=6(v+2)-2v

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Solution for 8=6(v+2)-2v equation: 



8=6(v+2)-2v

We move all terms to the left:

8-(6(v+2)-2v)=0



We calculate terms in parentheses: -(6(v+2)-2v), so:

6(v+2)-2v

We add all the numbers together, and all the variables

-2v+6(v+2)

We multiply parentheses

-2v+6v+12

We add all the numbers together, and all the variables

4v+12

Back to the equation:

-(4v+12)



We get rid of parentheses

-4v-12+8=0

We add all the numbers together, and all the variables

-4v-4=0

We move all terms containing v to the left, all other terms to the right

-4v=4

v=4/-4

v=-1

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