6(x-3)-3(x-2)=5+(3-x)

Solution for 6(x-3)-3(x-2)=5+(3-x) equation:

6(x-3)-3(x-2)=5+(3-x)

We move all terms to the left:

6(x-3)-3(x-2)-(5+(3-x))=0

We add all the numbers together, and all the variables

6(x-3)-3(x-2)-(5+(-1x+3))=0

We multiply parentheses

6x-3x-(5+(-1x+3))-18+6=0


We calculate terms in parentheses: -(5+(-1x+3)), so:

5+(-1x+3)

determiningTheFunctionDomain
(-1x+3)+5

We get rid of parentheses

-1x+3+5

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)


We add all the numbers together, and all the variables

3x-(-1x+8)-12=0

We get rid of parentheses

3x+1x-8-12=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5