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6-6x^2=-480
We move all terms to the left:
6-6x^2-(-480)=0
We add all the numbers together, and all the variables
-6x^2+486=0
a = -6; b = 0; c = +486;
Δ = b2-4ac
Δ = 02-4·(-6)·486
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*-6}=\frac{-108}{-12} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*-6}=\frac{108}{-12} =-9 $
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