6(x-3)-3(2x+1)=4(2x+1)-23

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Solution for 6(x-3)-3(2x+1)=4(2x+1)-23 equation: 



6(x-3)-3(2x+1)=4(2x+1)-23

We move all terms to the left:

6(x-3)-3(2x+1)-(4(2x+1)-23)=0

We multiply parentheses

6x-6x-(4(2x+1)-23)-18-3=0



We calculate terms in parentheses: -(4(2x+1)-23), so:

4(2x+1)-23

We multiply parentheses

8x+4-23

We add all the numbers together, and all the variables

8x-19

Back to the equation:

-(8x-19)



We add all the numbers together, and all the variables

-(8x-19)-21=0

We get rid of parentheses

-8x+19-21=0

We add all the numbers together, and all the variables

-8x-2=0

We move all terms containing x to the left, all other terms to the right

-8x=2

x=2/-8

x=-1/4

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