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6(x-3)-2=5(x+8)
We move all terms to the left:
6(x-3)-2-(5(x+8))=0
We multiply parentheses
6x-(5(x+8))-18-2=0
We calculate terms in parentheses: -(5(x+8)), so:We add all the numbers together, and all the variables
5(x+8)
We multiply parentheses
5x+40
Back to the equation:
-(5x+40)
6x-(5x+40)-20=0
We get rid of parentheses
6x-5x-40-20=0
We add all the numbers together, and all the variables
x-60=0
We move all terms containing x to the left, all other terms to the right
x=60
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