(y+3)(y-3)-y(y+5)-1=0

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Solution for (y+3)(y-3)-y(y+5)-1=0 equation: 



(y+3)(y-3)-y(y+5)-1=0

We use the square of the difference formula

y^2-y(y+5)-9-1=0

We multiply parentheses

y^2-y^2-5y-9-1=0

We add all the numbers together, and all the variables

-5y-10=0

We move all terms containing y to the left, all other terms to the right

-5y=10

y=10/-5

y=-2

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