3m=2(m-15)+12

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Solution for 3m=2(m-15)+12 equation: 



3m=2(m-15)+12

We move all terms to the left:

3m-(2(m-15)+12)=0



We calculate terms in parentheses: -(2(m-15)+12), so:

2(m-15)+12

We multiply parentheses

2m-30+12

We add all the numbers together, and all the variables

2m-18

Back to the equation:

-(2m-18)



We get rid of parentheses

3m-2m+18=0

We add all the numbers together, and all the variables

m+18=0

We move all terms containing m to the left, all other terms to the right

m=-18

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