1/3(12-24v)=2(4v-2)

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Solution for 1/3(12-24v)=2(4v-2) equation: 



1/3(12-24v)=2(4v-2)

We move all terms to the left:

1/3(12-24v)-(2(4v-2))=0



Domain of the equation: 3(12-24v)!=0

v∈R



We add all the numbers together, and all the variables

1/3(-24v+12)-(2(4v-2))=0

We multiply all the terms by the denominator


-((2(4v-2)))*3(-24v+12)+1=0



We calculate terms in parentheses: -((2(4v-2)))*3(-24v+12), so:

(2(4v-2)))*3(-24v+12

We add all the numbers together, and all the variables

-24v+(2(4v-2)))*3(+12

Back to the equation:

-(-24v+(2(4v-2)))*3(+12)



We add all the numbers together, and all the variables

-(-24v+(2(4v-2)))*312+1=0

We move all terms containing v to the left, all other terms to the right

-(-24v+(2(4v-2)))*312=-1

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