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6(x-2)-2=3x+3(-5+x)
We move all terms to the left:
6(x-2)-2-(3x+3(-5+x))=0
We add all the numbers together, and all the variables
6(x-2)-(3x+3(x-5))-2=0
We multiply parentheses
6x-(3x+3(x-5))-12-2=0
We calculate terms in parentheses: -(3x+3(x-5)), so:We add all the numbers together, and all the variables
3x+3(x-5)
We multiply parentheses
3x+3x-15
We add all the numbers together, and all the variables
6x-15
Back to the equation:
-(6x-15)
6x-(6x-15)-14=0
We get rid of parentheses
6x-6x+15-14=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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