4z+12=6z

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Solution for 4z+12=6z equation: 



4z+12=6z

We move all terms to the left:

4z+12-(6z)=0

We add all the numbers together, and all the variables

-2z+12=0

We move all terms containing z to the left, all other terms to the right

-2z=-12

z=-12/-2

z=+6

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