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6(x-2)-2=3x+3(-5+x
We move all terms to the left:
6(x-2)-2-(3x+3(-5+x)=0
We add all the numbers together, and all the variables
6(x-2)-(3x+3(x-5)-2=0
We multiply parentheses
6x-(3x+3(x-5)-2-12=0
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