6(x-2)-(3x+4)=4(3x+2)

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Solution for 6(x-2)-(3x+4)=4(3x+2) equation: 



6(x-2)-(3x+4)=4(3x+2)

We move all terms to the left:

6(x-2)-(3x+4)-(4(3x+2))=0

We multiply parentheses

6x-(3x+4)-(4(3x+2))-12=0

We get rid of parentheses

6x-3x-(4(3x+2))-4-12=0



We calculate terms in parentheses: -(4(3x+2)), so:

4(3x+2)

We multiply parentheses

12x+8

Back to the equation:

-(12x+8)



We add all the numbers together, and all the variables

3x-(12x+8)-16=0

We get rid of parentheses

3x-12x-8-16=0

We add all the numbers together, and all the variables

-9x-24=0

We move all terms containing x to the left, all other terms to the right

-9x=24

x=24/-9

x=-2+2/3

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