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13=1/2(2x+2+5x+3)
We move all terms to the left:
13-(1/2(2x+2+5x+3))=0
Domain of the equation: 2(2x+2+5x+3))!=0We add all the numbers together, and all the variables
x∈R
-(1/2(7x+5))+13=0
We multiply all the terms by the denominator
-(1+13*2(7x+5))=0
We calculate terms in parentheses: -(1+13*2(7x+5)), so:We add all the numbers together, and all the variables
1+13*2(7x+5)
determiningTheFunctionDomain 13*2(7x+5)+1
Wy multiply elements
26x(7+1
Back to the equation:
-(26x(7+1)
-(26x8=0
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