8y(2+3-4)+40=10

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Solution for 8y(2+3-4)+40=10 equation: 



8y(2+3-4)+40=10

We move all terms to the left:

8y(2+3-4)+40-(10)=0

We add all the numbers together, and all the variables

8y1+40-10=0

We add all the numbers together, and all the variables

8y+30=0

We move all terms containing y to the left, all other terms to the right

8y=-30

y=-30/8

y=-3+3/4

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