6(x-2)+8=2(x-10)

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Solution for 6(x-2)+8=2(x-10) equation: 



6(x-2)+8=2(x-10)

We move all terms to the left:

6(x-2)+8-(2(x-10))=0

We multiply parentheses

6x-(2(x-10))-12+8=0



We calculate terms in parentheses: -(2(x-10)), so:

2(x-10)

We multiply parentheses

2x-20

Back to the equation:

-(2x-20)



We add all the numbers together, and all the variables

6x-(2x-20)-4=0

We get rid of parentheses

6x-2x+20-4=0

We add all the numbers together, and all the variables

4x+16=0

We move all terms containing x to the left, all other terms to the right

4x=-16

x=-16/4

x=-4

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