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(4x+3)(7x-5)=0
We multiply parentheses ..
(+28x^2-20x+21x-15)=0
We get rid of parentheses
28x^2-20x+21x-15=0
We add all the numbers together, and all the variables
28x^2+x-15=0
a = 28; b = 1; c = -15;
Δ = b2-4ac
Δ = 12-4·28·(-15)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-41}{2*28}=\frac{-42}{56} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+41}{2*28}=\frac{40}{56} =5/7 $
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