(3c-2)-7c=40-2c

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Solution for (3c-2)-7c=40-2c equation: 



(3c-2)-7c=40-2c

We move all terms to the left:

(3c-2)-7c-(40-2c)=0

We add all the numbers together, and all the variables

(3c-2)-7c-(-2c+40)=0

We add all the numbers together, and all the variables

-7c+(3c-2)-(-2c+40)=0

We get rid of parentheses

-7c+3c+2c-2-40=0

We add all the numbers together, and all the variables

-2c-42=0

We move all terms containing c to the left, all other terms to the right

-2c=42

c=42/-2

c=-21

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