6(x+4)-5=21-4x-2+10x

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Solution for 6(x+4)-5=21-4x-2+10x equation: 



6(x+4)-5=21-4x-2+10x

We move all terms to the left:

6(x+4)-5-(21-4x-2+10x)=0

We add all the numbers together, and all the variables

6(x+4)-(6x+19)-5=0

We multiply parentheses

6x-(6x+19)+24-5=0

We get rid of parentheses

6x-6x-19+24-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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