-3y(-2y)+9=-3(4y-y)+7+11y

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Solution for -3y(-2y)+9=-3(4y-y)+7+11y equation: 



-3y(-2y)+9=-3(4y-y)+7+11y

We move all terms to the left:

-3y(-2y)+9-(-3(4y-y)+7+11y)=0

We add all the numbers together, and all the variables

-3y(-2y)-(-3(+3y)+7+11y)+9=0

We multiply parentheses

6y^2-(-3(+3y)+7+11y)+9=0



We calculate terms in parentheses: -(-3(+3y)+7+11y), so:

-3(+3y)+7+11y

determiningTheFunctionDomain
-3(+3y)+11y+7

We add all the numbers together, and all the variables

11y-3(+3y)+7

We multiply parentheses

11y-9y+7

We add all the numbers together, and all the variables

2y+7

Back to the equation:

-(2y+7)



We get rid of parentheses

6y^2-2y-7+9=0

We add all the numbers together, and all the variables

6y^2-2y+2=0

a = 6; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·6·2
Δ = -44
Delta is less than zero, so there is no solution for the equation

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