-4(3x-2)=5(2x+1)+13

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Solution for -4(3x-2)=5(2x+1)+13 equation: 



-4(3x-2)=5(2x+1)+13

We move all terms to the left:

-4(3x-2)-(5(2x+1)+13)=0

We multiply parentheses

-12x-(5(2x+1)+13)+8=0



We calculate terms in parentheses: -(5(2x+1)+13), so:

5(2x+1)+13

We multiply parentheses

10x+5+13

We add all the numbers together, and all the variables

10x+18

Back to the equation:

-(10x+18)



We get rid of parentheses

-12x-10x-18+8=0

We add all the numbers together, and all the variables

-22x-10=0

We move all terms containing x to the left, all other terms to the right

-22x=10

x=10/-22

x=-5/11

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