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6(x+2)+4=5(x-1)=+x
We move all terms to the left:
6(x+2)+4-(5(x-1))=0
We multiply parentheses
6x-(5(x-1))+12+4=0
We calculate terms in parentheses: -(5(x-1)), so:We add all the numbers together, and all the variables
5(x-1)
We multiply parentheses
5x-5
Back to the equation:
-(5x-5)
6x-(5x-5)+16=0
We get rid of parentheses
6x-5x+5+16=0
We add all the numbers together, and all the variables
x+21=0
We move all terms containing x to the left, all other terms to the right
x=-21
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