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6(x+1)=6+(x+1)
We move all terms to the left:
6(x+1)-(6+(x+1))=0
We multiply parentheses
6x-(6+(x+1))+6=0
We calculate terms in parentheses: -(6+(x+1)), so:We get rid of parentheses
6+(x+1)
determiningTheFunctionDomain (x+1)+6
We get rid of parentheses
x+1+6
We add all the numbers together, and all the variables
x+7
Back to the equation:
-(x+7)
6x-x-7+6=0
We add all the numbers together, and all the variables
5x-1=0
We move all terms containing x to the left, all other terms to the right
5x=1
x=1/5
x=1/5
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