0.44x2-40x-400=0

Solution for 0.44x2-40x-400=0 equation:

0.44x^2-40x-400=0

a = 0.44; b = -40; c = -400;
Δ = b2-4ac
Δ = -402-4·0.44·(-400)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-48}{2*0.44}=\frac{-8}{0.88}
=-9+0.08/0.88
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+48}{2*0.44}=\frac{88}{0.88}
=100
$